Center is the point of intersection of diagonals. ⇒2x−3y=5......(i) ⇒3x−4y=7........(ii) are diameter of circle so, point of intersection is centre of circle.from (1) & (2), x=1, y=−1 ∴ area of circle is 154 =πr2=154 r2=
7
22
×154 =
7×14
2
r2=49 ⇒ r = 7 ∴ Equation of circle with centre (1,−1) and radius 7 units ⇒(x−1)2+(y+1)2=72 ⇒x2+1−2x+y2+1+2y=49 ⇒x2+y2−2x+2y=49−2 ⇒x2+y2−2x+2y=47