VITEEE 2013 Solved Paper

In the steady state, current through capacitor

Using Kirchhof's voltage law to the circuit ACD
We have, 10 - 2 + 1 x R + 1 x 2 = 0
or R = 10Ω
Potential difference across C and D
VC−VD = 2 x 1 = 2V
As VD = 0V
So, VC = 2V
Potential difference across capacitor = 4 - 2 = 2V
∴ Charge on capacitor Q = C V = 2µF x 2 = 4µC