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VITEEE 2013 Solved Paper
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© examsnet.com
Question : 61
Total: 120
Acid hydrolysis of ester is first order reaction and rate constant is given by k =
2.303
t
log
V
∞
−
V
0
V
∞
−
V
t
where ,
V
,
V
t
and
V
∞
are the volumle of standard NaOH required to neutralise acid present at a given time, if ester is 50% neutralised then
V
∞
=
V
t
V
∞
=
(
V
t
−
V
0
)
V
∞
=
2
V
t
−
V
0
V
∞
=
2
V
t
+
V
0
Validate
Solution:
RCOOR' +
H
2
O
H
+
→
RCOOH + R'OH
At
t
=
0
a
0
0
At
time
t
a
−
x
x
x
At
time
∞
a
−
a
a
a
At t = 0 ,
V
0
= volume of NaOH due to
H
+
(catalyst)
V
t
= x +
V
0
V
∞
= a +
V
0
If ester is 50% hydrolysed then, x =
a
2
or
V
t
=
a
2
+
V
0
or a =
2
V
t
−
2
V
0
∴
V
∞
=
2
V
t
−
2
V
0
+
V
0
=
2
V
t
−
V
0
© examsnet.com
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