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VITEEE 2014 Solved Paper
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© examsnet.com
Question : 59
Total: 120
A gaseous mixture containing He ,
C
H
4
and
S
O
2
was allowed to effuse through a fine hole then find what molar ratio of gases coming out initially? (Given mixture contains He,
C
H
4
and
S
O
2
in 1 : 2 : 3 mole ratio).
√
2
:
√
2
:
3
2 : 2 : 3
4 : 4 : 3
1 : 1 : 3
Validate
Solution:
n
′
H
e
n
′
C
H
4
=
1
2
√
16
4
=
1
1
n
′
H
e
n
′
S
O
2
=
1
3
√
64
4
=
4
/
*
3
So, molar ratio will be,
n
′
H
e
:
n
′
C
H
4
:
n
′
S
O
2
= 4 : 4 : 3
© examsnet.com
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