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VITEEE 2015 Solved Paper
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© examsnet.com
Question : 4
Total: 120
The angular momentum of an electron in Bohr’s hydrogen atom whose energy is -3.4 eV, is
5
h
2
π
h
2
π
h
π
2
h
3
π
Validate
Solution:
Energy of Energy of electron in nth orbit of atom
E
n
= -
13.6
n
2
eV
⇒ 3.4 =
*
−
13.6
n
2
⇒
n
2
= 4
or n = 2
Angular momentum of electron
L =
n
h
2
π
=
2
h
2
π
=
h
π
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