2L of 3M AgNO3 will contains 6 moles of AgNO3. 3F of 1 M BaCl2 will contain 3 moles of BaCl2 2AgNO3+BaCl2 → 2AgCl + Na(NO3)2 So, 6 moles of AgNO3 will react with 3 moles on BaCl2 it means, two solution will react completely to form 3 moles of Ba(NO3)2 = 6 moles of NO3− ions in 2 + 3 = 5L solution Hence, molarity of NO3− =