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VITEEE 2016 Solved Paper
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© examsnet.com
Question : 23
Total: 125
The current density varies with radial distance r as J = a
r
2
, in a cylindrical wire of radius R. The current passing through the wire between radial distance R/3 and R/2 is
65
π
a
R
4
2592
25
π
a
R
4
72
65
π
a
2
R
3
2938
81
π
a
2
R
4
144
Validate
Solution:
Given ; J =
a
r
2
i =
2
∫
1
J × 2π r dr =
R
∕
2
∫
R
∕
3
a
r
52
× 2 π r dr
= 2πa
R
∕
2
∫
R
∕
3
r
3
dr =
2
π
a
|
r
4
4
|
R
∕
3
R
∕
2
=
π
a
2
[
(
R
2
)
4
−
(
R
3
)
4
]
=
π
a
R
4
2
×
65
81
×
16
=
65
π
a
R
4
2592
© examsnet.com
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