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VITEEE 2017 Solved Paper
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© examsnet.com
Question : 3
Total: 125
If the kinetic energy of a moving particle is E, then the de-Broglie wavelength is
λ = h
√
2
m
E
λ = h
√
2
m
E
h
λ =
h
√
2
m
E
λ =
h
E
√
2
m
E
Validate
Solution:
E =
1
2
m
v
2
or mv =
√
2
m
E
so λ =
h
m
v
=
h
√
2
m
E
© examsnet.com
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