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VITEEE 2017 Solved Paper
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© examsnet.com
Question : 57
Total: 125
Standard entropies of
X
2
,
Y
2
and
X
Y
3
are 60, 30 and 50
J
K
−
1
m
o
l
−
1
respectively. For the reaction
1
2
X
2
+
3
2
Y
2
⇄
X
Y
3
, ΔH = - 30 kJ to be at equilibrium, the temperature should be:
750 K
1000 K
1250 K
500 K
Validate
Solution:
ΔS = for the reaction
1
2
X
2
+
3
2
Y
2
⇄
X
Y
3
ΔS = 50 - (30 + 60) = - 40 J
For equilibrium ΔG =0 = ΔH - TΔS
T =
Δ
H
Δ
S
=
−
30000
−
40
= 750 K
© examsnet.com
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