If rate = k [A]x[B]y[C]z From first two given data 8.08 x 10−3 = k [0.2]x[0.1]y[0.02]z .... (1) 2.01 x 10−3 = k [0.1]x[0.2]y[0.02]z .... (2) Divide (1) by (2) we get, 4 = 2X (
1
2
)y Similarly, from second and third data (9)y(9)z = 3 2y+ 2z = 1. From first and fourth data 4Z = 8 = 23 2z = 3. So z = 3/2, y = - 1, x = 1