XeF2 has a linear shape. Its hybridization is sp 3d which means it should have a trigonal bipyramidal shape. Since it has 3 lone pairs, they occupy the equatorial triangle. XeF4 has sp 3d2 hybridization. It has a square planar shape and 2 lone pair of electrons. XeF6 has one lone pair of electrons. The 6 out of 8 electrons of Xenon are shared by 6 atoms of fluorine. Hence option D is the right answer.