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VITEEE 2018 Solved Paper
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© examsnet.com
Question : 88
Total: 125
If the parabola
y
2
= 4ax passes through the point (1, -2), then the tangent at this point is
x + y- 1 = 0
x-y-1 = 0
x + y + l = 0
x-y- 1 = 0
Validate
Solution:
Since the parabola
y
2
= 4ax passes through the point (1, -2),
∴
(
−
2
)
2
= 4a(1) ⇒ a = 1
Equation of tangent to the parabola at
(1,-2) is
y
y
1
= 2a(x +
x
1
) or x + y + 1 = 0
© examsnet.com
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