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VITEEE 2019 Solved Paper
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© examsnet.com
Question : 103
Total: 125
The equation of the plane which bisects the angle between the planes
3
x
−
6
y
+
2
z
+
5
=
0
and
4
x
−
12
y
+
3
z
−
3
=
0
which contains the origin is
33
x
−
13
y
+
32
z
+
45
=
0
x
−
3
y
+
z
−
5
=
0
33
x
+
13
y
+
32
z
+
45
=
0
None of these
Validate
Solution:
Equation of plane bisecting the angle containing origin is (making constant term of same sign)
−
3
x
+
6
y
−
2
z
−
5
√
3
2
+
6
2
+
2
2
=
+
[
4
x
−
12
y
+
3
z
−
3
√
4
2
+
12
2
+
3
2
]
or
−
3
x
+
6
y
−
2
z
−
5
7
=
4
x
−
12
y
+
3
z
−
3
13
or
67
x
−
162
y
+
47
z
+
44
=
0
.
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