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VITEEE 2019 Solved Paper
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© examsnet.com
Question : 3
Total: 125
If the kinetic energy of a free electron doubles, it’s de-Broglie wavelength changes by the factor
2
1
2
√
2
1
√
2
Validate
Solution:
de-Broglie wavelength
λ
−
h
p
=
h
√
2.
m
.
(
K
.
E
.
)
∴
λ
∝
1
√
K
.
E
.
If K.E is doubled, then de-Broglie wavelength becomes
λ
√
2
© examsnet.com
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