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VITEEE 2019 Solved Paper
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© examsnet.com
Question : 93
Total: 125
Evaluate
lim
x
→
2
√
(
x
+
7
)
−
3
√
(
2
x
−
3
)
3
√
(
x
+
6
)
−
2
3
√
(
3
x
−
5
)
17
9
17
18
34
23
26
7
Validate
Solution:
We have
L
=
lim
x
→
2
√
(
x
+
7
)
−
3
√
(
2
x
−
3
)
3
√
(
x
+
6
)
−
2
3
√
(
3
x
−
5
)
(
0
0
form
)
Let
x
−
2
=
t
such that when x → 2, t → 0. Then
L
=
lim
t
→
0
(
t
+
9
)
1
2
−
3
(
2
t
+
1
)
1
2
(
t
+
8
)
1
3
−
2
(
3
t
+
1
)
1
3
(
0
0
form
)
=
3
2
lim
t
→
0
(
1
+
t
9
)
1
2
−
(
2
t
+
1
)
1
2
(
1
+
t
8
)
1
3
−
(
3
t
+
1
)
1
3
(
0
0
form
)
=
3
2
lim
t
→
0
1
2
t
9
−
(
2
t
)
1
2
t
8
1
3
−
(
3
t
)
1
3
=
3
2
1
18
−
1
1
24
−
1
=
34
23
© examsnet.com
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