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VITEEE 2021 Solved Paper
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© examsnet.com
Question : 4
Total: 80
A soap bubble of radius
r
1
is placed on another soap bubble of radius
r
2
(
r
1
<
r
2
)
. The radius
R
of the soapy film separating the two bubbles is
r
2
+
r
2
r
2
−
r
1
r
1
r
2
r
1
r
2
r
2
−
r
1
√
r
1
2
+
r
2
2
Validate
Solution:
Excess pressure in a soap bubble of radius
r
1
=
4
T
r
1
Excess pressure in a soap bubble of radius
r
2
=
4
T
r
2
The excess pressure of a soapy film separating the two bubbles with
R
as the radius of common surface
=
4
T
R
Now
4
T
R
=
4
T
r
1
−
4
T
r
2
1
R
=
1
r
1
−
1
r
2
1
R
=
r
2
−
r
1
r
1
r
2
R
=
r
1
r
2
r
2
−
r
1
© examsnet.com
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