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VITEEE 2021 Solved Paper
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© examsnet.com
Question : 47
Total: 80
The position of both, an electron and a helium atom is known within
1.0
nm
. Further the momentum of the electron is known within
5.0
×
10
−
26
kg
ms
−
1
. The minimum uncertainty in the measurement of the momentum of the helium atom is
50
kg
ms
−
1
80
kg
ms
−
1
8.0
×
10
−
26
kg
ms
−
1
5.0
×
10
−
26
kgms
−
1
Validate
Solution:
By Heisenberg uncertainty Principle
Δ
x
×
Δ
p
=
h
4
π
(which is constant)
As
Δ
x
for electron and helium atom is same thus momentum of electron and helium will also be same therefore the momentum of helium atom is equal to
5
×
10
−
26
kg
.
m
.
s
−
1
.
© examsnet.com
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