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VITEEE 2022 Solved Paper

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Question : 42

Total: 125

200‌mL of an aqueous solution of a protein contains its 1.26g. The osmotic pressure of this solution at 300K is found to be 2.57×10−3 bar. The molar mass of protein will be
(R=0.083L‌ bar mol ‌−1K−1)

51022gmol−1
122044gmol−1
31011gmol−1
61038gmol−1

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