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Xavier Aptitude Test 2011 Solved Paper
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© examsnet.com
Question : 30
Total: 101
What is the maximum possible value of
(
21
Sin
X
+
72
C
o
s
X
)
?
21
57
63
75
None of the above
Validate
Solution:
(d)
y
=
21
sin
x
+
72
cos
x
.
.
.
(
1
)
d
y
d
x
=
21
cos
x
−
72
sin
x
=
0
tan
x
=
21
72
=
7
24
sin
x
=
7
√
7
2
+
24
2
,
cos
x
=
24
√
7
2
+
24
2
Put these value in
(
1
)
y
max
=
21
×
7
√
7
2
+
24
2
+
72
×
24
√
7
2
+
24
2
=
21
×
7
+
72
×
24
(
√
7
2
+
24
2
)
=
1875
25
=
75
© examsnet.com
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