Area of A APS = Area of rectangle ABCD - Area Δ APB -Area ΔQPC - Area ΔDQR- Area Δ ARS - Area Δ PQS Let’s assume the dimensions of rectangle ABCD as length, AB =32 and width BC =24 Thus, Area
ΔAPS=32×24−
1
2
×32×12−
1
2
×16×12−
1
4
Area ΔARQ−
3
4
Area ΔPRQ ...... (1)
Now, Area ΔARQ =Area of rectangle ADQE - Area of Δ DRQ-AreaΔAQS =16×24−
1
2
×16×12−
1
2
×24×16 =384−96−192=96 And Area ΔPRQ= Area of rectangle CDRP-AreaΔDRQ− Area