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Question : 19
Total: 28
An object is placed at a distance of 60 cm 30 cm
(i) Use lens formula to find the distance of the image from the lens.
(ii) List four characteristics of the image (nature, position, size, erect/inverted) formed by the lens in this case.
(iii) Draw ray diagram to justify your answer of part (ii).
(i) Use lens formula to find the distance of the image from the lens.
(ii) List four characteristics of the image (nature, position, size, erect/inverted) formed by the lens in this case.
(iii) Draw ray diagram to justify your answer of part (ii).
Solution:
(i)
=
−
+
=
u = − 60
f = − 30
(In case of Concave lens)
Hence, putting the values in formula, we get
+
=
=
=
=
∴ v = − 20 cm
∵ m =
=
= 0.33
(ii) So, the image formed will be virtual, erect, small in size and image will be formed20 cm
(In case of Concave lens)
Hence, putting the values in formula, we get
(ii) So, the image formed will be virtual, erect, small in size and image will be formed
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