CBSE Class 12 Math 2013 Solved Paper

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Question : 19
Total: 29
Evaluate:
4
0
|x| + |x - 2| + |x - 4| dx
Solution:  
4
0
|x| + |x - 2| + |x - 4| dx
=
2
0
f (x) dx +
4
2
f (x) dx
=
2
0
x - x + 2 - x + 4 dx +
4
2
x + x - 2 - x + 4 dx
=
2
0
6 - x dx +
4
2
x + 2 dx
= |6x
x2
2
|
02
+ |
x2
2
+2x
|
04

= 12 - 2 + 8 + 8 - 2 - 4 = 20
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