CBSE Class 12 Math 2022 Term I Solved Paper

Question : 39

Total: 50

If x=−4 is a root of |

x	2	3
1	x	1
3	2	x

|=0, then the sum of the other two roots is

4
-3
2
5

Solution: 👈: Video Solution

‌ Explanation: Given, ‌|

x	2	3
1	x	1
3	2	x

|=0
⇒‌‌x(x2−2)−2(x−3)+3(2−3x)
⇒‌‌x3−13x+12=0
Since (x+4) is one root of above cubic equation.
‌ Sum roots ‌=0
∴‌‌ Sum of two roots +(−4)=0
Sum of two roots =4

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