CBSE Class 12 Physics 2017 Delhi Set 1 Paper

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Question : 19
Total: 26
(i) A radioactive nucleus ' A ' undergoes a series of decays as given below:
A
α
A1
β
A2
α
A3
γ
A4

The mass number and atomic number of A2 are 176 and 71 respectively.
Determine the mass and atomic numbers of A4 and A.
(ii) Write the basic nuclear processes underlying β+and βdecays.
Solution:  
(i) Determining the mass and atomic number of A4 and A
(ii) Basic nuclear processes of β+and βdecays
(i) A4: Mass Number : 172

Atomic Number : 69
A : Mass Number : 180
Atomic Number : 72
[Alternatively : Give full credit if student considers decay and find atomic and mass numbers accordingly
72180A
α
70176
A1
β+
71176A2
α
69172A3
γ
69172A4

Gives the values quoted above.
If the student takes β+decay
72180A
α
70176
A1
β+
71176A2
α
69172A3
γ
69172A4

This would give the answers: (A4:172,69);(A:180,74)]
(ii) Basic nuclear process for β+decay pn+10e +v
For βdecay np+10e+v
[Note: Give full credit of this part, if student writes the processes as conversion of proton into neutron for decay and neutron into proton for decay.]
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