CBSE Class 12 Physics 2017 Delhi Set 1 Paper

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Question : 20
Total: 26
(i) A ray of light incident on face AB of an equilateral glass prism, shows minimum deviation of 30. Calculate the speed of light through the prism.

(ii) Find the angle of incidence at face AB so that the emergent ray grazes along the face AC.
Solution:  
(i) Calculation of speed of light
(ii) Calculation of angle of incidence at face AB
(i) µ=
sin(
A+δm
2
)
sin(
A
2
)

=
sin(
60+30
2
)
sin(
60
2
)
=2

Also µ=
c
v
v
=
3×108
2
m
s

v=2.122×108m s
(ii)

At face AC, let the angle of incidence be r2.
For grazing ray, e=90
µ=
1
sinr2
r2
=sin1(
1
2
)
=45

Let angle of refraction at face AB be r1.
Now r1+r2=A
r1=Ar2=6045=15
Let angle of incidence at this face be i
µ=
sini
sinr1

µ=2=
sini
sin15

i=sin1(2sin15)
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