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CBSE Class 12 Physics 2017 Delhi Set 3 Paper

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Question : 3
Total: 8
An α -particle and a proton are accelerated through the same potential difference. Find the ratio of their de Broglie wavelengths.
Solution:  
Finding the ratio of de Broglie wavelength
(‌
λα
λp
)
λ=‌
h
p
=‌
h
√2mK
=‌
h
√2mqV
∴‌
λα
λp
=‌
h
√2mαqαV
×‌
√2mpqpV
h
‌
λα
λp
‌=‌
√mpqp
√mαqα

‌=‌
√mpqp
√4mp2qp

‌=‌
1
2√2

λα:λp‌=1:2√2
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