CBSE Class 12 Physics 2017 Delhi Set 3 Paper

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Question : 7
Total: 8
Two identical capacitors of 12pF each are connected in series across a battery of 50V. How much electrostatic energy is stored in the combination? If these were connected in parallel across the same battery, how much energy will be stored in the combination now?
Also find the charge drawn from the battery in each case.
Solution:  
Equivalent capacitance in series
Energy in series combination
Charge in series combination
Equivalent capacitance in parallel combination
Energy in parallel combination
Charge in parallel combination

In series combination :
1
Cs
=(
1
12
+
1
12
)
(pF)1

Cs=6×1012pF
Us=
1
2
Cs
V2

Us=
1
2
×6
×1012
×50
×50J

Us=75×1010J
qs=CsV
=6×1012×50
=300×1012C=3×1010C

In parallel combination :
Cp=(12+12)pF
Cp=24×1012F
Up=
1
2
×24
×1012
×2500J

Us=3×108J
qp=CpV
qp=24×1012×50C
qp=1.2×109C
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