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Question : 7
Total: 8
Two identical capacitors of 12 pF each are connected in series across a battery of 50 V . How much electrostatic energy is stored in the combination? If these were connected in parallel across the same battery, how much energy will be stored in the combination now?
Also find the charge drawn from the battery in each case.
Also find the charge drawn from the battery in each case.
Solution:
Equivalent capacitance in series
Energy in series combination
Charge in series combination
Equivalent capacitance in parallel combination
Energy in parallel combination
Charge in parallel combination
In series combination :
= (
+
) ( pF ) − 1
C s = 6 × 10 − 12 pF
U s =
C s V 2
U s =
× 6 × 10 − 12 × 50 × 50 J
U s = 75 × 10 − 10 J
q s = C s V
= 6 × 10 − 12 × 50
= 300 × 10 − 12 C = 3 × 10 − 10 C
In parallel combination :
C p = ( 12 + 12 ) pF
∴ C p = 24 × 10 − 12 F
U p =
× 24 × 10 − 12 × 2500 J
U s = 3 × 10 − 8 J
q p = C p V
q p = 24 × 10 − 12 × 50 C
q p = 1.2 × 10 − 9 C
Energy in series combination
Charge in series combination
Equivalent capacitance in parallel combination
Energy in parallel combination
Charge in parallel combination
In series combination :
In parallel combination :
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