CBSE Class 12 Physics 2017 Delhi Set 3 Paper

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Question : 8
Total: 8
(a) Write the expression for the force
F
acting on a particle of mass m and charge q moving with velocity
V
in a magnetic field
B
. Under what conditions will it move in (i) a circular path and (ii) a helical path?
(b) Show that the kinetic energy of the particle moving in magnetic field remains constant.
Solution:  
(a) Expression for force acting on charged particle 1
(i) Condition for circular path
(ii) Condition for helical path
(b) Showing Kinetic energy is constant
(a)
F
=q(
v
×B
)

(i) When velocity of charged particle and magnetic field are perpendicular to each other.
(ii) When velocity is neither parallel nor perpendicular to the magnetic field.
(b) The force, experienced by the charged particle, is perpendicular to the instantaneous velocity, at all instants. Hence the magnetic force cannot bring any change in the speed of the charged particle. Since speed remains constant, the kinetic energy also stays constant.
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