CBSE Class 12 Physics 2017 Outside Delhi Set 1 Paper

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Question : 21
Total: 26
(a) State Biot - Savart law and express this law in the vector form.
(b) Two identical circular coils, P and Q each of radius R, carrying currents 1A and 3A respectively, are placed concentrically and perpendicular to each other lying in the XY and YZ planes. Find the magnitude and direction of the net magnetic field at the centre of the coils.
Solution:  
(a) Statement of Biot Savart law
Expression in vector form
Magnitude of magnetic field at centre
Direction of magnetic field
(a) It states that magnetic field strength,
dB
, due to a current element,
Idl
, at a point, having a position vector r relative to the current element, is found to depend (i) directly on the current element, (ii) inversely on the square of the distance |r| , (iii) directly on the sine of angle between the current element and the position vector r.

In vector notation,
dB
=
µ0
4π
Idi
×
r
|
r
|
3

(b) Bπ=
µ0×1
2R
=
µ0
2R
( along z direction)
BQ=
µ0×3
2R
=
µ03
2R
(along x direction)
B=Bp2+BQ2=
µ0
R

This net magnetic field B, is inclined to the field Bp, at an angle θ, where
tanθ=3
(θ=tan13=60)
(in XZ plane)
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