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Question : 22
Total: 26
Two identical parallel plate capacitors A and B are connected to a battery of V volts with the switch S closed. The switch is now opened and the free space between the plates of the capacitors is filled with a dielectric of dielectric constant K . Find the ratio of the total electrostatic energy stored in both capacitors before and after the introduction of the dielectric.
Solution:
Formula for energy stored
Energy stored before
Energy stored after
Ratio
Energy stored=
C V 2 ( =
)
Net capacitance with switchS closed
= C + C = 2 C
Energy stored=
× 2 C × V 2 = C V 2
After the switch S is opened, capacitance each capacitor of= K C
∴ Energy stored in capacitor A =
K C V 2
For capacitor B,
Energy stored=
=
=
∴ Total Energy stored
=
K C V 2 +
=
C V 2 ( K +
)
=
C V 2 (
)
∴ Required ratio =
=
Energy stored before
Energy stored after
Ratio
Energy stored
Net capacitance with switch
Energy stored
After the switch S is opened, capacitance each capacitor of
For capacitor B,
Energy stored
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