CBSE Class 12 Physics 2019 Outside Delhi Set 1 Paper

Question : 2

Total: 27

A proton is accelerated through a potential difference V, subjected to a uniform magnetic field acting normal to the velocity of the proton. If the potential difference is doubled, how will the radius of the circular path described by the proton in the magnetic field change?

Solution:

For writing the expression for radius
To find the change in the radius of the circular orbit

Alternatively,
‌r=‌

√‌

2mV

‌r′=√2r
‌r∝√V
‌‌

r′

=√2

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