CBSE Class 12 Physics 2020 Delhi Set 1 Paper

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Question : 28
Total: 37
SECTION - C

(a) Differentiate between electrical resistance and resistivity of a conductor.
(b) Two metallic rods, each of length L, area of crosssection A1 and A2 having resistivity ρ1 and ρ2 are connected in parallel across a d.c. battery. Obtain the expression for the effective resistivity of this combination.
Solution:  
(a)
 Electrical resistance  Resistivity
 It is the property of material due to which it opposes the flow of electricity through the conductor  The resistivity is defined as the resistance of a material of 1 metre length and 1 square metre area of cross section.
 Unit: Ohm  Unit: Ohm-Meter
 Symbol: R  Symbol: ρ
 Length, cross-section area of conductor and temperature  Depends on temperature and material of the conductor

(b) For resistor R1
Resistivity =ρ1
Length =L
Area =A1
R1=ρ1×
L
A1

For resistor R2
Resistivity =ρ2
Length =L
Area =A2
R2=ρ2×
L
A2

For the equivalent resistor
Resistivity =ρ
Length =L
Area =A=A1+A2
R=ρ×
L
A

Since the resistors are connected parallel
Equivalent resistance =R=
R1R2
R1+R2

Or, ρ×
L
A
=
ρ1L
A1
×
ρ2L
A2
ρ1L
A1
+
ρ2L
A2

ρ= Effective resistivity =
ρ1ρ2(A1+A2)
ρ1A2+ρ2A1
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