CBSE Class 12 Physics 2023 Outside Delhi Set 1 Paper

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Question : 1
Total: 35
SECTION - A

The magnitude of the electric field due to a point charge object at a distance of 4.0m is 9
N
C
. From the same charged object the electric field of magnitude, 16
N
C
will be at a distance of
In 1st case,
E=
kq
r2

Or, 9=
kq
42
[r=4.0m]

kq=9×16
In 2nd case,
E=
kq
(r)2

Or, 16=
9×16
(r)2

Or, (r)2=9
r=3m
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