CBSE Class 12 Physics 2023 Outside Delhi Set 1 Paper

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Question : 11
Total: 35
A hydrogen atom makes a transition from n=5 to n=1 orbit. The wavelength of photon emitted is λ. The wavelength of photon emitted when it makes a transition from n=5 to n=2 orbit is
In 1‌st ‌ case
‌‌
1
λ
‌
=R[‌
1
12
−‌
1
52
]

‌ or, ‌‌‌
1
λ
‌
=R[1−‌
1
25
]
=R[‌
24
25
]

∴‌R‌=‌
25
24
×
‌
1
λ

In 2‌nd ‌ case
1
λ′
‌
=R[‌
1
22
−‌
1
52
]

‌ or, ‌‌‌‌
1
λ′
‌
=R[‌
1
4
−‌
1
25
]
=R×‌
21
100

‌ or, ‌‌‌
1
λ′
‌
=‌
25
24
×
‌
1
λ
×
‌
21
100

‌ or, ‌‌‌
1
λ′
‌
=‌
21
96λ

∴‌λ′‌=‌
96
21
λ
=‌
32
7
λ
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