ICSE Class 10 Physics 2016 Solved Paper
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A battery of emf 12 V and internal resistance 2 Ω is connected with two resistors A and B of resistance 4 Ω and 6 Ω respectively joined in series.
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Find:
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Question : 61
Total: 73
Current in the circuit.
Solution:
Given : V = 12 V , Resistance of A = 4 Ω , Resistance of B = 6 Ω , Internal battery resistance = 2 Ω .
Total Resistance = 4 + 6 + 2
= 12 Ω .
I (current in circuit) =
=
= 1 amp .
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