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ICSE Class 10 Physics 2017 Solved Paper

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A pulley system with VR=4 is used to lift a load of 175‌kgf through a vertical height of 15m. The effort required is 50‌kgf in the downward direction. (g=10Nkg−1)
Calculate:
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Question : 28
Total: 65
Distance moved by the effort.
Solution:  
Given : V.R. =4, Load =175‌kgf, displacement of load (dL)=15m., Effort =50 kgf, g=10Nkg−1
Distance moved by the effort (dE)= ?
We know,
‌ V.R. ‌‌=‌
dE
dL
⇒‌‌dE‌=‌ V.R. ‌×dL=4×15
‌=60m
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