ICSE Class 10 Physics 2020 Solved Paper

The diagram above shows three resistors connected across a cell of e.m.f. 1.8V and internal resistance r. Calculate:

Question : 52

Total: 67

Current through 3Ω resistor.

Solution:

Let the current through 3Ω resistor be ' i '
A. So the current through 1.5Ω resistor will be (0.3−i) A. As 3Ω resistor and 1.5Ω resistor are in parallel. So,
‌3×i‌=1.5(0.3−i)
⇒‌3i‌=0.45−1.5i
⇒‌4.5i‌=0.45
=‌

0.45

4.5

=0.1A

Go to Question:

Prev Question

Next Question