ICSE Class 10 Physics 2020 Solved Paper
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The diagram above shows three resistors connected across a cell of e.m.f.1.8 V and internal resistance r . Calculate:
The diagram above shows three resistors connected across a cell of e.m.f.
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Question : 53
Total: 67
The internal resistance r .
Solution:
In the given diagram, 3 Ω and 1.5 Ω resistor are in parallel.
∴
=
+
=
=
∴ R p = 1 Ω
NowR p and 4 Ω resistances are in series
∴ R s = 1 + 4 = 5 Ω
So net external resistance of the circuit= 5 Ω
We know, I =
⇒ 0 ⋅ 3 =
⇒ 0.3 ( 5 + r ) = 1.8
⇒ ( 5 + r ) = 6
⇒ r = 6 − 5
r = 1 Ω
Now
So net external resistance of the circuit
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