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ICSE Class X Math 2014 Solved Paper

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In the figure given below, O is the centre of the circle. AB and CD are two chords of the circle. OM is perpendicular to AB and ON is perpendicular to CD.

AB=24‌cm,OM=5‌cm,ON=12‌cm.‌ Find ‌ the :
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Question : 49
Total: 52
radius of the circle.
Solution:  
‌‌ Given : ‌AB=24‌cm;OM=5‌cm,ON=12 ‌cm.
∵OM‌⟂‌AB
M is mid point of AB .
∴AM=12‌cm.

Let radius of circle =r
From △ AMO;
AO2=AM2+OM2
(By Pythagoras theorem)
r2‌=(12)2+(5)2
‌=144+25=169
r‌=13‌cm.
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