ICSE Class X Math 2014 Solved Paper

Show Para  Hide Para 
In the figure given below, O is the centre of the circle. AB and CD are two chords of the circle. OM is perpendicular to AB and ON is perpendicular to CD.

AB=24cm,OM=5cm,ON=12cm. Find the :
© examsnet.com
Question : 50
Total: 52
length of chord CD.
Solution:  
Now from CNO ;
CO2=ON2+CN2
r2=(12)2+CN2
(AO=CO=r)
(13)2(12)2=CN2
169144=CN2
CN2=25
CN=5
As ONCD,N is mid point of CD .
CD=2CN=2×5=10cm
© examsnet.com
Go to Question: