ICSE Class X Math 2014 Solved Paper
Show Para
In the figure given below, O is the centre of the circle. A B and C D are two chords of the circle. O M is perpendicular to A B and O N is perpendicular to C D .
A B = 24 cm , O M = 5 cm , O N = 12 cm . Find the :
© examsnet.com
Question : 50
Total: 52
length of chord CD.
Solution:
Now from ∆ CNO ;
CO 2 = ON 2 + CN 2
r 2 = ( 12 ) 2 + CN 2
( ∵ AO = CO = r )
( 13 ) 2 − ( 12 ) 2 = CN 2
169 − 144 = CN 2
⇒ CN 2 = 25
⇒ CN = 5
AsON ⟂ CD , N is mid point of CD .
∴ CD = 2 CN = 2 × 5 = 10 cm
As
© examsnet.com
Go to Question: