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NCERT Class XI Chemistry Equilibrium Solutions

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Question : 14
Total: 73
One mole of H2O and one mole of CO are taken in 10 L vessel and heated to 725 K. At equilibrium 40% of water (by mass) reacts with CO according to the equation, H2O(g)+CO(g) ⇌ H2(g)+CO2(g). Calculate the equilibrium constant for the reaction.
Solution:  
From the above reaction,
H2O(g)+CO(g) ⇌ H2(g)+CO2(g)
Initial‌no.of‌moles1100
At‌equilibrium0.60.60.40.4

∴ [H2O] =
0.6
10
‌mol‌L−1 = 0.06 mol‌L−1 ; [CO] =
0.6
10
‌mol‌L−1 = 0.06 mol‌L−1;
[H2] =
0.4
10
 = 0.04 mol‌L−1 and [CO2] =
0.4
10
 = 0.04 mol‌L−1
Kc =
H2][CO2]
[H2O][CO]
 =
0.4
10
×
0.4
10
0.6
10
×
0.6
10
 = 0.44
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