NCERT Class XI Chemistry Equilibrium Solutions

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Question : 15
Total: 73
At 700 K, equilibrium constant for the reaction : H2(g)+I2(g)2Hl(g) is 54.8. If 0.5 molL1 of HI(g) is present at equilibrium at 700 K, what are theconcentration of H2(g) and I2(g) assuming that we initially started with HI(g) and allowed it to reach equilibrium at 700 K?
Solution:  
2Hl(g)H2(g)+I2(g)
Initialconcentrationa00
Atequilibrium0.5xx

Kc =
[H2][I2]
[HI]2
or ,
1
54.8
=
x×x
(0.5)2
or x2 =
0.25
54.8
⇒ x = 0.068
[H2] = [I2] = 0.068 mollitre1
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