NCERT Class XI Chemistry Equilibrium Solutions

Question : 16

Total: 73

What is the equilibrium concentration of each of the substances in the equilibrium when the initial concentration of ICl was 0.78 M?
2ICl(g) ⇌ I2(g)+Cl2(g) ; Kc = 0.14

Solution:

2ICl(g) ⇌ I2(g)+Cl2(g) ; Kc = 0.14

Initial‌molar‌conc.	0.78	0	0
Eqm.molar‌conc.	0.78−2x	x	x

Applying law of chemical equilibrium,
Kc =

[I2][Cl2]

[ICl]2

⇒ 0.14 =

x.x

(0.78−2x)2

x2 = 0.14 (0.78−2x)2
or

0.78−2x

= √0.14 = 0.374 or x = 0.292 - 0.748 x
or 1.748x = 0.292 or x = 0.167
Hence at equilibrium, [I2] = [Cl2] = 0.167 M
[ICl] = 0.78 – 2 × 0.167 = 0.446 M

Go to Question:

Prev Question

Next Question