NCERT Class XI Chemistry Equilibrium Solutions

© examsnet.com
Question : 22
Total: 73
Bromine monochloride, BrCl decomposes into bromine and chlorine and reaches the equilibrium :
2BrCl(g)Br2(g)+Cl2(g)
For which Kc = 32 at 500 K. If initially pure BrCl is present at a concentration of 3.3 × 103molL1, what is its molar concentration in the mixture at equilibrium?
Solution:  
2BrCl(g)Br2(g)+Cl2(g)
Initial3.30×103molL100
Ateqm.(3.30×103x)
x
2
x
2

Kc =
(
x
2
)
(
x
2
)
(3.30×103x)2
= 32 (Given)
x2
4(3.30×103x)2
= 32 or ,
x
2(3.30×103x)
= 32 = 5.66
or, x = 11.32 (3.30 × 103 – x) or, 12.32x = 11.32 × 3.30 × 103 or, x = 3.0 × 103
∴ At eqm., [BrCl] = (3.30 × 103 – 3.0 × 103) = 0.30 × 103 = 3.0 × 104molL1
© examsnet.com
Go to Question: