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NCERT Class XI Chemistry Equilibrium Solutions

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Question : 3
Total: 73
At a certain temperature and total pressure of 105 Pa, iodine vapour contains 40% by volume of I atoms. I2(g) ⇌ 2I(g) Calculate Kp for the equilibrium.
Solution:  
I2(g)
1→1−x
 ⇌ 2
I(g)
0−2x
Total moles at equilibrium = 1 – x + 2x = 1 + x
But
2x
1+x
 = 0.4 (Given)
∴ x =
1
4
So, mole fraction of I2 =
1−
1
4
1+
1
4
 =
3
5
 = 0.6, mole fraction of I =
2×
1
4
1+
1
4
 =
2
5
 = 0.4
pI = 0.4 × 105Pa, pI2 = 0.6 × 105Pa
Kp =
pI2
PI2
 =
(0.4)2(105)2
(0.6)(105)
 = 2.67 × 104
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