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NCERT Class XI Chemistry Equilibrium Solutions

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Question : 5
Total: 73
Find out the value of Kc of each of the following equilibria from the value of Kp :
(i) 2NOCl(g) ⇌ 2NO(g)+Cl2(g) ; Kp = 1.8 × 10–2 at 500 K
(ii) CaCO3(s) ⇌ CaO(s)+CO2(g) ; Kp = 167 at 1073 K
Solution:  
(i) Kp = Kc(RT)Δng, Δng = (2 + 1) – 2 = 1
1.8 × 10–2 = Kc (0.0821 × 500), Kc = 4.38 × 10–4
(ii) Δng = 1 , Kc =
Kp
(RT)
 =
167
(0.0821×1073)
 = 1.896
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