NCERT Class XI Chemistry Some Basic Concepts of Chemistry Solutions

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Question : 12
Total: 36
If the density of methanol is 0.793 kgL1, what is its volume needed for making 2.5 L of its 0.25 M solution?
Solution:  
Moles of methanol present in 2.5 L of 0.25 M solution
Molarity =
MolesofCH3OH
Volumeinlitre
⇒ 0.25 =
MolesofC3OH
2.5

∴ Moles of CH3OH = 2.5 × 0.25 = 0.625
∴ Mass of CH3OH = 0.625 × 32 = 20 g
[∴ Molecular mass of CH3OH = 12 + 1 × 3 + 16 + 1 = 32]
∴ 0.793 × 103 g of CH3OH is present in 1000 mL
∴ 20 g of CH3OH is present in =
1000
0.793×103
× 20 = 25.2 mL
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