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NCERT Class XI Chemistry States of Matter Solutions

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Question : 15
Total: 23
Calculate the total pressure in a mixture of 8 g of dioxygen and 4 g of dihydrogen confined in a vessel of 1 dm3 at 27°C. R = 0.083 bar dm3K–1mol–1
Solution:  
Partial pressure of oxygen gas,
P =
nRT
V
 , n =
8
32
 mol , V = 1 dm3 , T = 300 K
P(O2) =
8×0.083×300
32×1
 = 6.255 bar
Partial pressure of hydrogen gas, P =
nRT
V
 , n =
4
2
 = 2 mol
P(H2) =
2×0.083×300
1
 = 49.8 bar
Total pressure = P(O2)+P(H2) = 6.225 + 49.8 = 56.025 bar
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