NCERT Class XI Chemistry States of Matter Solutions
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Question : 16
Total: 23
Payload is defined as the difference between the mass of displaced air and the mass of the balloon. Calculate the payload when a balloon of radius 10 m, mass 100 kg is filled with helium at 1.66 bar at 27°C. (Density of air =1.2 k g m – 3 and R = 0.083 bar d m 3 K – 1 m o l – 1 )
Solution:
Volume of balloon =
π r 3 , Radius of balloon, r = 10 m
V =
× 3.14 × ( 10 ) 3 = 4186.7 m 3
Mass of displaced air = 4186.7m 3 × 1.2 k g m – 3 = 5024.04 kg
Moles of gas present =
=
= 279.11 × 10 3 moles
Mass of helium present = 279.11 ×10 3 × 4 = 1116.44 × 10 3 g = 1116.44 kg
Mass of filled balloon = 100 + 1116.44 = 1216.44 kg
Payload = Mass of displaced air – Mass of balloon
= 5024.04 – 1216.44 = 3807.6 kg
V =
Mass of displaced air = 4186.7
Moles of gas present =
Mass of helium present = 279.11 ×
Mass of filled balloon = 100 + 1116.44 = 1216.44 kg
Payload = Mass of displaced air – Mass of balloon
= 5024.04 – 1216.44 = 3807.6 kg
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