NCERT Class XI Chemistry Structure of Atom Solutions
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Question : 35
Total: 67
If the diameter of a carbon atom is 0.15 nm, calculate the number of carbon atoms which can be placed side by side in a straight line across length of scale of length 20 cm long.
Solution:
A carbon atom covers length = diameter of atom = 0.15 nm
= 0.15 ×10 – 9 × 102 cm = 0.15 × 10 – 7 cm
∴ Number of carbon atoms which can be placed on 20 cm length
=
= 1.33 × 10 9
= 0.15 ×
∴ Number of carbon atoms which can be placed on 20 cm length
=
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